2011年6月11日 星期六

HKDSE數學必修部分模擬試題卷二題解 Solutions to HKDSE Maths Compulsory Part Paper 2 (Sample Paper) - Part 1

以下是HKDSE數學試卷必修部分卷二(英文版下載中文版下載)第1~10題的答案。

(注意:若你正在尋找考評局2012年1月出版的練習試題答案,請參閱此頁。)

如欲查閱第11~20題答案,請參閱題解Part 2

如欲查閱第21~30題答案,請參閱題解Part 3

如欲查閱第31~45題答案,請參閱題解Part 4

請注意:此試題題解只供英文版本,歡迎轉載,但請提供來源(網址: http://hkdsefighter.blogspot.com/2011/06/hkdse-hkdse-maths-compulsory-part-paper_11.html。)

1. The answer is C.
(3a)2(a3)
=9a2(a3)
=9a5

2. The answer is C.
5-3m=2n
5-2n=3m
m=(5-2n)÷3

3. The answer is C.
a2-b2 +2b-1
=a2-(b2 -2b+1)
=a2-(b-1)2
=[a+(b-1)][a-(b-1)]
=(a-b+1)(a+b-1)

4. The answer is A.
L.H.S.=x2+px+(5p+q)
R.H.S.=x2+3x-10
p=3, 5p+q=-10
Therefore, 5(3)+q=10
q=-25

5. The answer is C.
f(-2)
=(-2)3+2(-2)2-7(-2)+3
=-8+8+14+3
=17 (Remainder Theorem)

6. The answer is D.
(x-a)(x-a-1)=(x-a)
(x-a)[(x-a-1)-1]=0
(x-a)(x-a-2)=0
x-a=0 or x-a-2=0
x=a or x=a+2

7. The answer is D.
x2-6x=2-k
x2-6x+(k-2)=0
Discriminant
=(-6)2-4(1)(k-2)
=36-4(k-2)
=36-4k+8
=44-4k<0
Therefore,
-4k<-44
k>11

8. The answer is A.
III is wrong because the mid-point of A and B should be where the axis of symmetry passes through. As the x-coordinate of the mid-point is (1+7)÷2=4, the axis of symmetry should be x=4. So III is wrong and the answer is A.

9. The answer is C.
5-2x<3
-2x<-2
x>1

4x+8>0
4x>-8
x>-2

The result is x>1 and x>-2.
The range that satisfies both domains will be x>1.

10. The answer is A.
Total cost of the handbags= 240÷(1+20%)+240÷(1-20%)= $500
Total selling price= 240(2)= $480
So the girl has lost $20.





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